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![SOLVED: Calculate the CO and CS bond lengths in OCS from the rotational constants BC1e0-zC zS) 6081.5 MHz; BC-801zC3+S) = 5932.8 MHz: [4]](https://cdn.numerade.com/ask_previews/7293009a-cc1c-4f2e-a0f5-b38d20c77bd2_large.jpg "SOLVED: Calculate the CO and CS bond lengths in OCS from the rotational constants BC1e0-zC zS) 6081.5 MHz; BC-801zC3+S) = 5932.8 MHz: [4]")
SOLVED: Calculate the CO and CS bond lengths in OCS from the rotational constants BC1e0-zC zS) 6081.5 MHz; BC-801zC3+S) = 5932.8 MHz: [4]
Mean Free Path, Molecular Collisions
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![Calculate the mean free path in CO2 at 27^∘C and a pressure of 10^-9 bar. Molecular diameter of CO2 is 500 pm.[ Given : R = 25/3 J.mol^-1K^-1, √(2) = 1.4, pi = 22/7, NA = 6 × 10^23 ]](https://d1hhj0t1vdqi7c.cloudfront.net/v1/T3o5V3VEaEc5MVU=/sd/ "Calculate the mean free path in CO2 at 27^∘C and a pressure of 10^-9 bar. Molecular diameter of CO2 is 500 pm.[ Given : R = 25/3 J.mol^-1K^-1, √(2) = 1.4, pi = 22/7, NA = 6 × 10^23 ]")
Calculate the mean free path in CO2 at 27^∘C and a pressure of 10^-9 bar. Molecular diameter of CO2 is 500 pm.[ Given : R = 25/3 J.mol^-1K^-1, √(2) = 1.4, pi = 22/7, NA = 6 × 10^23 ]
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